[Potironette]

m = 2.1 * 10^3 kg
angle = 20.0 degrees
F_f = 4.0 * 10^3 N
v_f = 3.8 m/s

F_g = mg
F_g = (2.1 * 10^3 kg) * 9.81 m/s^2 = 20601 N = 2.1 * 10^4 N


F_N = cos(20.0 degrees) * F_g
F_N = cos(20.0 degrees) * (2.1 * 10^4 N)
F_N = 19733.5 N = 2.0 * 10 ^4 N
don't need this because I'm not calculating for friction related things, I think.

F_x' = sin(20.0 degrees) * F_g
F_x' = sin(20.0 degrees) * (2.1 * 10^4 N)
F_x' = 7182.42 N = 7200 N

F_net = F_x' - F_f
F_net = 7200 N - 4.0 * 10^3 N = 3200 N

F_net = ma
F_net/m = a
3200 N / (2.1 * 10^3 kg) = a
a = 1.5 m/s^2

a = v/t
t = v/a
t = 3.8 m/s / 1.5 m/s^2
t = 2.5 s

d = d_i + v_i*t + .5at^2
d = .5at^2
d = .5(1.5 m/s^2)*2.5^2
d = 4.7 m


This way is simpler :o! So, ultimately I can use the position equation because I can solve for the acceleration, initial velocity and time? Is this something that I just need to do a lot of problems for before recognizing a sort of pattern :/ ?

Thanks for helping me with this!