[Potironette]

Ohh okay, that makes sense! In other words, if the stuff was already accelerating, the t when they ball and the platform coincide would be even longer, and the t from the moment the ball fell to the moment the ...do you mean to find the velocity, first one needs to use some other time, then later plug the velocity into the ball equation and then the t when the two equal each other is the time they coincide?

Ball: y = 10 + v*t - (1/2)g*t^2
Platform: y = 0 + (1/2)a*t^2